Loading notes…

Solid State ChemistryBurdwan University · B.Sc. (NEP) · Inorganic
Electronic properties Chapter 6 · Electronic Properties & Superconductivity

Electronic Properties & Superconductivity

Why does copper conduct electricity but diamond does not, even though both are crystals? This chapter answers that. We start with the simple free-electron picture, then build the band theory that explains conductors, semiconductors and insulators — and end with the magical world of superconductors.

⚡ Drude–Lorentz Theory🌊 Band Theory💡 Semiconductors🧊 Superconductors
⚡

Free-Electron Theory (Drude–Lorentz, 1900)

Basic idea. In a metal, the valence electrons leave their atoms and move freely through the whole crystal, like gas molecules in a container. This moving crowd of electrons is called the electron gas (or electron sea). The positive ions sit fixed in the lattice.

Free-Electron Model
Free-Electron (Drude) Model of a Metal + + + + + + + + + + + + free electrons drift among fixed positive ions — this is why metals conduct
In the Drude picture, valence electrons wander freely through a fixed lattice of positive ions.

Postulates of the theory:

  1. A metal contains a large number of free electrons — the valence electrons detached from their atoms — moving randomly among fixed positive ion cores.
  2. Between two collisions, an electron travels in a straight line with constant velocity. Collisions happen only between electrons and ion cores, and each collision randomises the electron's velocity.
  3. In the absence of an electric field the motion is completely random, so the average velocity is zero — no current flows.
  4. When an electric field is applied, the electrons acquire a small average drift velocity opposite to the field — this drift is the electric current.
  5. The electron gas obeys the classical Maxwell–Boltzmann statistics, exactly like an ideal gas. (This last assumption turned out to be wrong — Sommerfeld later replaced it with Fermi–Dirac statistics.)

Successes of the theory:

  • Explains Ohm's law — current is proportional to the applied field (V = IR).
  • Explains the high electrical and thermal conductivity of metals — the same free electrons carry both charge and heat.
  • Explains the Wiedemann–Franz law: the ratio of thermal conductivity (κ) to electrical conductivity (σ) is proportional to absolute temperature.
Wiedemann–Franz law: κ / (σT) = L  ·  L (Lorentz number) ≈ 2.44 × 10−8 W·Ω·K−2

Failures of the theory:

  • Heat capacity: the theory predicts the electrons should contribute 3R/2 per mole to the heat capacity, but experiments show the electronic contribution is almost negligible (the observed 3R comes from lattice vibrations).
  • Temperature dependence: the theory predicts conductivity σ ∝ 1/√T, but experiments give σ ∝ 1/T for metals.
  • It cannot explain why some solids are conductors, some are semiconductors and some are insulators.
  • It cannot explain the positive Hall coefficient observed in some metals (which needs positive charge carriers — holes).
Memory trick: Drude's theory is like treating electrons as a gas — it explains flow (current, heat) well, but fails wherever the quantum nature of electrons matters (heat capacity, bands). The examiner loves asking "successes and failures of free-electron theory" as a 5-mark question — learn both lists by heart.
🌊

Band Theory of Solids

How bands form. A single atom has sharp energy levels. When N atoms come close together to form a solid, each atomic orbital splits into N very closely spaced levels. These merge into a continuous energy band. The inner orbitals overlap little and give narrow bands; the outer (valence) orbitals overlap strongly and give broad bands.

  • Valence band: the highest energy band that contains electrons (at 0 K it is completely filled in semiconductors and insulators).
  • Conduction band: the next higher band, which is empty at 0 K. Electrons here move freely and conduct electricity.
  • Forbidden gap (Eg): the energy gap between the top of the valence band and the bottom of the conduction band. No electron can stay in this gap.
Band Diagrams
Energy Bands: Conductor, Semiconductor, Insulator E E E EF EF EF Conductor no gap — bands overlap Semiconductor small gap ≈ 1 eV Insulator large gap > 3 eV
Shaded = filled with electrons. The band gap decides everything: none → conductor, small → semiconductor, large → insulator.
Density of States in 3D, 2D, 1D, 0D
Density of States in 3D, 2D, 1D, 0D E D(E) 3D D ~ √E E D(E) 2D constant E D(E) 1D D ~ 1/√E E D(E) 0D sharp lines
3D: D∝√E · 2D: constant · 1D: D∝1/√E · 0D: sharp lines — asked in the 2023 & 2024 PYQs.

Classification of solids from band theory:

TypeBand pictureEnergy gap EgBehaviour with temperatureExamples
ConductorsValence and conduction bands overlap — no gapEg = 0Conductivity decreases on heating (vibrating ions scatter electrons)Na, Cu, Al, Fe
SemiconductorsSmall gap between bandsSmall, ~1 eV (Si: 1.1 eV, Ge: 0.66 eV at 300 K)Conductivity increases on heating (more electrons jump the gap)Si, Ge
InsulatorsLarge gap between bandsLarge, > 3 eV (diamond: 5.5 eV)Practically no conduction at any ordinary temperatureDiamond, glass, rubber
Conductivity of an intrinsic semiconductor: σ = σ₀ · e−Eg/2kT  ·  conductivity rises exponentially with temperature.
Exam tip: This is one of the most repeated 5-mark questions: "Distinguish between conductors, semiconductors and insulators on the basis of band theory, with diagrams." Always draw the three band diagrams with labels (VB, CB, Eg), then add the table. A neat diagram alone can fetch 2 marks.
💡

Semiconductors: Intrinsic vs Extrinsic

Intrinsic semiconductors are pure crystals like Si and Ge. At 0 K they behave like insulators, but on heating some electrons jump the small gap from the valence band to the conduction band. Each jumping electron leaves behind a hole (a positive vacancy) in the valence band. Both the electron and the hole conduct electricity. Here the number of electrons equals the number of holes (n = p).

Extrinsic semiconductors are made by adding a tiny amount of impurity (about 1 atom in a million) to pure Si or Ge. This process is called doping, and it increases conductivity enormously. There are two types:

Featuren-type semiconductorp-type semiconductor
DopantPentavalent impurity — P, As, Sb (5 valence electrons)Trivalent impurity — B, Al, Ga, In (3 valence electrons)
What happens4 of the 5 electrons form bonds with Si; the 5th electron is almost freeOnly 3 bonds form with Si; the missing bond creates a hole
Extra energy levelDonor level — just below the conduction band; the extra electron easily jumps into the CBAcceptor level — just above the valence band; it easily accepts an electron, creating a hole in the VB
Majority carriersElectrons (negative)Holes (positive)
Minority carriersHolesElectrons
Doping Levels
Doping Silicon: n-type and p-type E conduction band valence band E conduction band valence band donor level P gives one extra electron acceptor level B creates a hole (+ carrier) n-type: P in Si p-type: B in Si
Donor level sits just below the conduction band (extra electron); acceptor level sits just above the valence band (hole left behind).
Memory trick: n-type uses peNtavalent dopants and carries current by Negative electrons. p-type uses trivalent dopants and carries current by positive holes. Remember: "n = Negative carriers, p = Positive carriers."
Effect of temperature: In metals, conductivity falls on heating because lattice vibrations scatter the electrons. In semiconductors, conductivity rises sharply on heating because more electrons get enough thermal energy to jump across the gap. This opposite behaviour is a favourite short question.
🧊

Superconductivity

Definition. Some materials, when cooled below a certain temperature, suddenly lose all electrical resistance — current flows forever without any loss. This phenomenon is called superconductivity, and the temperature below which it appears is the critical temperature (Tc). It was discovered by Kamerlingh Onnes in 1911 in mercury.

SuperconductorCritical temperature TcRemarks
Mercury (Hg)4.2 KThe first superconductor discovered (1911)
Lead (Pb)7.2 KA typical Type I superconductor
Nb3Sn~18 KA widely used Type II superconductor
YBa2Cu3O7 (YBCO)~92 KHigh-Tc ceramic; works above liquid-nitrogen temperature (77 K)
Mercury-based cuprate~135 KOne of the highest Tc values known at normal pressure

Meissner effect. A superconductor cooled below Tc does not just conduct perfectly — it actively expels all magnetic field lines from its interior (B = 0 inside). It behaves as a perfect diamagnet. This was discovered by Meissner and Ochsenfeld in 1933.

Meissner Effect
T > Tc — normal metal T < Tc — superconductor field lines pass through field expelled — Meissner effect perfect diamagnetism below Tc
Above Tc the magnetic field passes through; below Tc the superconductor expels it completely.
Exam tip — a very common trap: Zero resistance and the Meissner effect are NOT the same thing. A merely "perfect conductor" (zero resistance) would trap magnetic flux inside it, but a superconductor expels it. If the question asks "How is a superconductor different from a perfect conductor?", this one line is the full answer.

Type I vs Type II superconductors:

FeatureType I (soft) superconductorsType II (hard) superconductors
Critical fieldSingle critical field Hc — below Hc full Meissner state, above Hc normal stateTwo critical fields Hc1 and Hc2 — between them a mixed (vortex) state with partial flux penetration
Field strengthHc is small (a few hundredths of a tesla)Hc2 can be very large (tens of tesla)
TransitionSharp, sudden loss of superconductivity at HcGradual transition through the mixed state
ExamplesPb, Hg, Sn, AlNb3Sn, NbTi, YBa2Cu3O7
ApplicationsNot useful for magnets (low Hc)Used in MRI scanners, particle accelerators and maglev trains
BCS theory (one line): Bardeen, Cooper and Schrieffer (1957) explained superconductivity by saying that electrons pair up as Cooper pairs (through interaction with lattice vibrations), and these pairs move through the crystal without any resistance.
Memory trick for Tc values: think of the ladder 4 → 18 → 92 → 135: mercury at 4 K started it, Nb3Sn doubled the teens, YBCO crossed liquid nitrogen (77 K) at 92 K, and mercury-cuprates top the chart near 135 K.

✎ PYQ Zone — Chapter 6

Every previous-year question from this chapter's topics, with year, paper, marks and a full exam-ready answer. Tap a question to open its detailed solution.

2018B.Sc. CC-64 marks

Q3(b)(i) — “Write about the band theory of metals.” ⭐⭐⭐

📖 Detailed answer ▼

How bands form. An isolated atom has sharp energy levels. When a huge number (N) of atoms pack together into a crystal, each atomic orbital splits into N very closely spaced levels. These merge into a continuous energy band. Inner orbitals overlap little and give narrow bands; the outer valence orbitals overlap strongly and give broad bands.

Key terms:

  • Valence band: the highest band containing electrons (full at 0 K).
  • Conduction band: the next higher band — empty at 0 K; electrons here move freely and conduct.
  • Forbidden gap (Eg): the gap between the bands where no electron can stay.
  • Fermi level (EF): the energy of the highest filled state at 0 K.

Why metals conduct (band picture). In a metal the valence and conduction bands overlap (or the top band is only half-filled), so the Fermi level lies inside a band. Electrons just below EF can move into empty states just above it with almost no energy — so even a tiny electric field makes them flow. This is why metals conduct even at 0 K.

Contrast (one line each): in a semiconductor a small gap (Eg ≈ 0.5–3 eV) separates full and empty bands — heating pushes electrons across, so conductivity rises with T. In an insulator the gap is huge (Eg > 3–4 eV) — electrons cannot cross it, so there is practically no conduction.

Exam tip: always draw the three band diagrams (conductor: overlapping bands; semiconductor: small gap; insulator: large gap) with VB, CB, Eg and EF labelled — the diagram alone can fetch half the marks.
2018B.Sc. CC-63 marks🔁 2022

Q3(b)(ii) — “What are semiconductors? Give an example of n-type semiconductor.” ⭐⭐⭐⭐

Related: 2022 · B.Sc. CC-6 · Q1(h) (2 marks): “What are the p-type semiconductors? Give one example.”

📖 Detailed answer ▼

Semiconductors are solids whose electrical conductivity lies between conductors and insulators. In band terms they have a small forbidden gap (Eg ≈ 0.5–3 eV; Si: 1.1 eV, Ge: 0.66 eV) between a full valence band and an empty conduction band. At 0 K they behave like insulators, but heating gives some electrons enough energy to jump the gap, leaving holes behind — so their conductivity rises sharply with temperature (opposite to metals).

n-type semiconductor: pure Si or Ge doped with a tiny amount of pentavalent impurity (P, As, Sb). Four of the impurity’s five valence electrons form bonds with the host; the fifth electron stays loosely bound and is easily promoted into the conduction band. This creates a donor level just below the conduction band. Because current is carried mainly by negative charges (electrons), it is called n-type.

Example: phosphorus-doped silicon (Si:P).

2022 asked the partner question (Q1(h)) — p-type: doped with a trivalent impurity (B, Al, Ga); the missing bond creates a hole (positive carrier) and an acceptor level just above the valence band. Example: boron-doped silicon. Joining p-type and n-type gives a p–n junction, the basis of diodes.
2021B.Sc. CC-65 marks

Q1 (second half) — “The electrical conductivity of metal decreases with the rise in temperature but the reverse occurs with semiconductors”-Explain. ⭐⭐⭐

Note: this was the second half of 2021 CC-6 Q1. The first half (“Water has its highest density at 4°C”-Explain) is not a solids question — do not mix the two while revising.

📖 Detailed answer ▼

Metals — conductivity decreases on heating. In a metal the conduction band already contains a huge number of free electrons, and heating hardly changes this number. But heating makes the lattice ions vibrate more strongly, and these vibrations scatter the moving electrons — the electrons collide more often and their drift slows down. Resistivity ρ rises (roughly linearly with T), so conductivity σ = 1/ρ falls.

Semiconductors — conductivity increases on heating. At low temperature almost all electrons sit in the full valence band and very few reach the conduction band. Heating gives exponentially more electrons enough thermal energy to jump the small band gap, creating electron–hole pairs. The number of charge carriers grows exponentially with T:

σ = σ0 · e−Eg/2kT

This flood of new carriers completely outweighs the extra scattering, so conductivity rises sharply with temperature — the exact opposite of a metal.

Exam tip (5 marks): draw two small labelled graphs — σ vs T falling for a metal and rising for a semiconductor — and write one line under each explaining the cause (scattering vs carrier generation). Diagram + cause + formula = full marks.
2023M.Sc. MSCH-1043½+… [unclear]🔁 2024

Q6(a) — “Define “density of states(D(E))” and show that it is proportional to (energy)-1/2. Write the expression of D(E) for a zero dimensional solid, one dimensional quantum wire and [two] dimensional thin film.” ⭐⭐⭐⭐

Repeated: 2024 · M.Sc. MSCH-104 · Q8(b) (Q8 carries 4+2+2): “Define ‘density of states’. Using this concept, write down the expression of ‘1D molecular wire’, ‘2D thin film’ and ‘0D quantum dots’.”

📖 Detailed answer ▼

Density of states D(E): the number of allowed quantum states per unit energy interval at energy E — D(E)·dE is the number of states between E and E + dE. It decides how many electron states are available to be filled, so it controls heat capacity, conductivity and optical properties of solids.

Derivation (1D — this gives the E−1/2 law). Confine a free electron to a wire of length L. Allowed wavevectors are quantised (k = nπ/L), so the number of k-states (counting both spins) up to wavevector k is

N = 2 · (L/2π) · 2k = 2Lk/π

For a free electron E = ℏ²k²/2m, so k = (2mE/ℏ²)1/2 and dk/dE = m/(ℏ²k). Differentiating,

D(E) = dN/dE = (2L/π)·(m/ℏ²k) = (L/π)·(2m/ℏ²)1/2·E−1/2

Hence D(E) ∝ E−1/2 in one dimension — it diverges (spikes) at low energy. These spikes are the van Hove singularities.

Expressions asked in the question:

  • 1D quantum wire: D(E) = (L/π)(2m/ℏ²)1/2E−1/2 ∝ 1/√E
  • 2D thin film (area A, per subband): D(E) = mA/(πℏ²) = constant — each subband adds a flat step
  • 0D solid / quantum dot: D(E) = 2Σnδ(E − En) — sharp delta-function lines, fully discrete atom-like levels

(For reference — 3D bulk: D(E) = (V/2π²)(2m/ℏ²)3/2E1/2 ∝ √E.)

Memory line: “Root-E, flat, spikes, lines” — 3D, 2D, 1D, 0D. For the 2024 short question, just state the energy dependence of each case — that earns full marks.
2023B.Sc. CC-92.5 marks

Q3(b)(ii) — “Boron nitride has a structure similar to graphite. Yet, graphite is a good conductor of electricity whereas boron nitride is not so.” — Account for this difference. ⭐⭐⭐

📖 Detailed answer ▼

The difference is in the band structure, not the geometry:

  • Graphite — conductor. Every carbon is identical and sp² bonded; the fourth valence electron of each C sits in a delocalised π-band spread over the whole layer. The valence and conduction π-bands touch at the Fermi level (no effective gap), so electrons move freely within the layers — graphite conducts (strongly anisotropically: along the layers, not between them).
  • Boron nitride — insulator. B and N have very different electronegativities, so the B–N bonds are strongly polar: the π-electrons are localised on the nitrogen atoms instead of being shared. This opens a huge band gap of about 6 eV — far too large for thermal excitation — so there are no free carriers and BN is an insulator (used as a ceramic precisely because it conducts heat but not electricity).

One line: identical atoms give graphite a delocalised π-band with no gap (conductor); polar B–N bonds localise the electrons and open a ~6 eV gap in BN (insulator).

2019B.Sc. DSE-16 marks (2+2+2)🔁 4 years

Q3(d)(i) — “Derive an expression of vibrational partition function for a Planck’s oscillator (classical). Hence arrive at the Einstein’s expression of molar heat capacity of a monatomic solid. Comment on its value at low and high temperature limit.” ⭐⭐⭐⭐⭐

Einstein theme repeated: 2020 · B.Sc. DSE-1 · Q9 (5 marks): “Starting from the expression of ‘average energy of an oscillator’ as per Planck’s formulation, arrive at the Einstein’s equation of heat capacity of solids. Which type of bonds do exist in polymers?” · 2022 · B.Sc. DSE-1 · Q3(a)(i) (4 marks): “Derive an expression for molar heat capacity (Cv) of a monoatomic solid according to Einstein model.” · 2024 · B.Sc. DSE-1 · Q3(c)(i) (4 marks): “If the energy of an oscillator vibrating with a frequency ν in one direction be given by, ε̄ = hν/(ehν/KT − 1), arrive at Einstein’s equation for heat capacity of solids. How far was the equation successful to explain the heat capacity values of solids?”

📖 Detailed answer ▼

Einstein model: each atom of the solid is an independent 3D quantum harmonic oscillator, and all oscillators vibrate with the same single frequency νE.

Step 1 — partition function of one 1D Planck oscillator. Energy levels En = nhν (n = 0, 1, 2, …; the constant zero-point energy hν/2 drops out of the heat capacity):

z = Σn=0∞ e−nhν/kT = 1 + e−hν/kT + e−2hν/kT + … = 1/(1 − e−hν/kT)

Each atom vibrates in three independent directions, so for one atom z3D = z³.

Step 2 — mean energy. From ε̄ = kT²(∂ln z/∂T):

ε̄ = hν/(ehν/kT − 1)   (per direction — this is Planck’s formula)

Step 3 — total energy of one mole. One mole has 3NA oscillators:

U = 3NA·hνE/(ehνE/kT − 1) = 3RT·(θE/T)/(eθE/T − 1),  θE = hνE/k

θE is the Einstein temperature.

Step 4 — heat capacity. CV = (∂U/∂T)V:

CV = 3R·(θE/T)²·eθE/T/(eθE/T − 1)²

Step 5 — the two limits (2 marks):

  • High T (T ≫ θE): θE/T is small, eθE/T ≈ 1 + θE/T, so CV → 3R — the Dulong–Petit law. ✓ Success.
  • Low T (T ≪ θE): CV ≈ 3R(θE/T)²e−θE/T → 0 exponentially. Going to zero is qualitatively right (third law), but experiment shows CV ∝ T³ (Debye T³ law) — the exponential fall is too fast. ✗ Failure.
How far was it successful? (asked in 2024): Einstein’s model was the first quantum explanation of why heat capacity falls at low T, and it gets the high-T 3R limit exactly right — but the single-frequency assumption is too crude: real solids have a range of coupled vibrational frequencies, which Debye’s model (continuous spectrum up to νD) handles correctly, giving the observed T³ law.
2022B.Sc. DSE-13 marks

Q3(c)(iv) — “State Debye T³ law and mention its utility.” ⭐⭐⭐

📖 Detailed answer ▼

Debye T³ law: at very low temperatures (T ≪ θD, the Debye temperature), the molar heat capacity of a solid is proportional to the cube of the absolute temperature:

CV = (12π⁴/5)·R·(T/θD)³ ≈ 234·R·(T/θD)³ ∝ T³

Why T³? At low T only the low-frequency acoustic vibrations (phonons) are thermally excited. Their density of states grows as ν², and only modes with hν ≲ kT are active — the number of excited modes ∝ T³, so the vibrational energy U ∝ T⁴ and CV = dU/dT ∝ T³.

Utility:

  • It correctly explains the low-temperature heat capacity where Einstein’s model fails (Einstein predicts an exponential fall, experiment gives T³).
  • Measuring the low-T heat capacity lets us determine the Debye temperature θD of a solid — a characteristic elastic property.
  • In metals, writing CV = γT + AT³ lets us separate the electronic (γT) and lattice (AT³) contributions by plotting CV/T against T².
2021B.Sc. DSE-15 marks

Q10(a) — “Write down the drawback of Einstein’s equation of heat capacity of solids. Mention the main difference between the assumptions of Einstein and that of Debye regarding the vibrations in solids.” ⭐⭐⭐

📖 Detailed answer ▼

Drawback of Einstein’s equation. Einstein assumes every atom vibrates independently with one single frequency νE. This predicts that at low temperature the heat capacity falls exponentially, CV ∝ e−θE/T — but experiments show it falls as T³ (Debye T³ law). The single-frequency assumption is too crude: in a real solid the atoms are coupled and vibrate with a whole range of frequencies. (The fitted θE also drifts with temperature instead of staying constant.)

Einstein vs Debye — the key difference in assumptions:

Einstein modelDebye model
Picture of vibrationAtoms are independent 3D oscillatorsAtoms are coupled; vibrations are collective elastic (sound) waves — phonons
FrequenciesOne single frequency νE for all atomsContinuous distribution from 0 up to a maximum νD, with g(ν) ∝ ν²
Low-T heat capacityFalls exponentially → 0 (too fast — disagrees with experiment)CV ∝ T³ — matches experiment
High-T heat capacity→ 3R (Dulong–Petit) ✓→ 3R (Dulong–Petit) ✓

One line: Einstein = independent oscillators, one frequency; Debye = coupled lattice, continuous spectrum up to νD — and that spectrum is what gives the correct T³ law at low temperature.

2023B.Sc. CC-91 mark

Q2(a)(ii) — “Mention one important property of polythiazyl.” ⭐⭐⭐

📖 Detailed answer ▼

Polythiazyl, (SN)x, shows metallic electrical conductivity — it was the first known conducting inorganic polymer (a “synthetic metal”). Its chains of alternating sulphur and nitrogen atoms carry a delocalised π-electron system along the backbone, so electrons move freely down the chains (conductivity of the order of 10³ S cm−1 along the chains). It even becomes superconducting below about 0.26 K.

One-line answer for 1 mark: polythiazyl is an inorganic polymer with metallic electrical conductivity along its (S–N)x chains.