Dear student, this is the most "diagram-loving" chapter of the unit. Examiners ask you to draw and describe unit cells of NaCl, CsCl, fluorite, diamond and perovskite almost every year. Learn one fact-table per structure: how the ions are arranged, which voids are filled, the coordination number and the number of formula units — that is the whole game.
In an AB type ionic solid, equal numbers of cations (A) and anions (B) pack together. Which structure forms depends mainly on the radius ratio r⁺/r⁻ — bigger cations need bigger coordination numbers. Three structures you must know are given below.
1. Rock Salt Structure — Sodium Chloride (NaCl)
Arrangement: Cl⁻ ions form a face-centred cubic (fcc) lattice; Na⁺ ions occupy all the octahedral voids.
Coordination number: 6 : 6 — each Na⁺ is surrounded by 6 Cl⁻ and each Cl⁻ by 6 Na⁺.
Formula units per unit cell (Z): 4 (4 Na⁺ + 4 Cl⁻).
Radius ratio: r(Na⁺)/r(Cl⁻) ≈ 0.52 — fits the octahedral range 0.414–0.732.
Other examples: KCl, MgO, CaO, AgCl, LiF, MnO.
Rock Salt (NaCl) Structure
Cl⁻ ions form an fcc lattice; Na⁺ ions fill every octahedral void — each ion is touched by 6 of the opposite kind (6:6).
2. Caesium Chloride Structure (CsCl)
Arrangement: Cl⁻ ions form a simple cubic lattice; one Cs⁺ ion sits at the body centre of the cube.
Coordination number: 8 : 8 — each Cs⁺ touches 8 Cl⁻ and vice versa.
Formula units per unit cell (Z): 1 (1 Cs⁺ + 1 Cl⁻).
Radius ratio: r(Cs⁺)/r(Cl⁻) ≈ 0.93 — above 0.732, so cubic (8-fold) coordination is stable.
Other examples: CsBr, CsI, TlCl, TlBr.
Caesium Chloride (CsCl) Structure
Cl⁻ ions sit at the corners of a cube with Cs⁺ at the body centre — each ion has 8 nearest neighbours of the opposite kind (8:8).
Exam tip: A very common 2-mark question: "Why does NaCl take the rock salt structure while CsCl takes the CsCl structure?" Answer: the Cs⁺ ion is much larger (r⁺/r⁻ ≈ 0.93), so 8 anions can fit around it; Na⁺ is smaller (r⁺/r⁻ ≈ 0.52), so only 6 anions fit comfortably. Always quote the radius-ratio ranges: 0.414–0.732 → octahedral (CN 6), above 0.732 → cubic (CN 8).
3. Zinc Blende vs Wurtzite (both ZnS)
Both are 4 : 4 coordinated structures of zinc sulphide. They differ only in the stacking of the sulphide ions. This comparison is a favourite 5-mark question.
Point
Zinc Blende
Wurtzite
Packing of S²⁻ ions
Cubic close packing (ccp / fcc)
Hexagonal close packing (hcp)
Stacking sequence
ABCABC…
ABAB…
Zn²⁺ ions occupy
Half of the tetrahedral voids
Half of the tetrahedral voids
Coordination number
4 : 4
4 : 4
Formula units per cell
4
2
Examples
ZnS (low temp.), CuCl, CdS, AgI
ZnS (high temp.), ZnO, CdS, BeO
Zinc Blende vs Wurtzite (ZnS)
Zinc blende stacks sulphide layers ABCABC (ccp); wurtzite stacks them ABAB (hcp). In both, Zn²⁺ fills half the tetrahedral voids — 4:4 coordination.
Memory trick:"Blende is Best in Cubic" — Blende = BCC-like? No! Remember: zinc Blende = Cubic packing (ccp), Wurtzite = Hexagonal packing (hcp). Both fill half the tetrahedral voids, CN 4:4.
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AB₂ Type Structures (1 : 2 compounds)
Here there are twice as many anions as cations. The cation usually has a higher coordination number than the anion.
1. Fluorite Structure — Calcium Fluoride (CaF₂)
Arrangement: Ca²⁺ ions form a ccp (fcc) lattice; F⁻ ions occupy all the tetrahedral voids.
Coordination number: 8 : 4 — each Ca²⁺ is surrounded by 8 F⁻, each F⁻ by 4 Ca²⁺.
Formula units per unit cell: 4 (4 Ca²⁺ + 8 F⁻).
Other examples: SrF₂, BaF₂, CdF₂, UO₂, ThO₂.
2. Antifluorite Structure — Sodium Oxide (Na₂O)
Arrangement: Exactly the reverse of fluorite — O²⁻ ions form the ccp lattice and Na⁺ ions occupy all the tetrahedral voids.
Coordination number: 4 : 8 — each Na⁺ is surrounded by 4 O²⁻ and each O²⁻ by 8 Na⁺.
Other examples: K₂O, Li₂O, Na₂S.
Fluorite (CaF₂) and Antifluorite (Na₂O)
In fluorite, Ca²⁺ forms a ccp array with F⁻ in every tetrahedral void (8:4). Antifluorite swaps the roles: O²⁻ in ccp, Na⁺ in the tetrahedral voids.
Memory trick:"Anti = opposite." In fluorite the cation makes the close packing; in antifluorite the anion makes the close packing. Coordination numbers simply swap: 8:4 becomes 4:8.
3. Rutile Structure — Titanium Dioxide (TiO₂)
Arrangement: O²⁻ ions are approximately hexagonal close packed; Ti⁴⁺ ions occupy half of the octahedral voids.
Coordination number: 6 : 3 — each Ti⁴⁺ by 6 O²⁻, each O²⁻ by 3 Ti⁴⁺.
Other examples: MnO₂, SnO₂, PbO₂, GeO₂, MgF₂.
4. Cadmium Iodide (CdI₂) — Layer Structure
Arrangement: I⁻ ions are hexagonal close packed; Cd²⁺ ions fill the octahedral voids of alternate layers only.
The result is a layered (sandwich) structure: I–Cd–I sheets held to each other only by weak van der Waals forces, so the crystals are soft and cleave easily.
Coordination number: 6 : 3. Other examples: CdBr₂, FeCl₂, Mg(OH)₂.
Exam tip: Learn the "who packs, who fills" line for each structure — one line per structure is enough: NaCl = fcc Cl⁻ + all octahedral Na⁺; CsCl = simple cubic Cl⁻ + body-centre Cs⁺; CaF₂ = ccp Ca²⁺ + all tetrahedral F⁻; Na₂O = reverse; TiO₂ = hcp O²⁻ + half octahedral Ti⁴⁺; diamond = ccp C + half tetrahedral C. Write these six lines and you can answer any 5-mark "describe" question.
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Perovskite Structure (ABX₃)
The mineral perovskite is CaTiO₃. The general formula is ABX₃, where A is a large cation, B a smaller cation and X usually oxygen (oxide perovskites) or a halide.
Ideal cubic structure
A²⁺ (Ca²⁺) — at the corners of the cube (coordination number 12).
B⁴⁺ (Ti⁴⁺) — at the body centre (coordination number 6, octahedral).
X²⁻ (O²⁻) — at the face centres (each B is surrounded by an octahedron of 6 X ions).
So the structure can be seen as a network of corner-sharing BX₆ octahedra with the large A cation sitting in the 12-coordinate cavity between them.
Perovskite Structure (CaTiO₃)
Ca²⁺ at the cube corners, Ti⁴⁺ at the body centre, O²⁻ at the face centres — the six oxides form a TiO₆ octahedron around titanium.
Tolerance factor and structural distortion
Whether the ideal cubic structure actually forms depends on the relative sizes of A, B and X. This is measured by the Goldschmidt tolerance factor:
t < 0.9 → A cation too small; the BX₆ octahedra tilt and the structure distorts to orthorhombic or rhombohedral symmetry (e.g. CaTiO₃ itself is orthorhombic at room temperature).
t > 1.0 → A cation too large; distortion towards hexagonal structures.
Memory trick: Think of the tolerance factor as a "fitting test". t = 1 is a perfect fit (cubic). Too small an A ion (t < 0.9) makes the octahedra tilt like a collapsing tent; too big an A ion (t > 1) stretches the structure hexagonal.
Ilmenite structure (FeTiO₃)
Ilmenite is related to the corundum (α-Al₂O₃) structure: O²⁻ ions are approximately hcp and the cations fill two-thirds of the octahedral voids.
The difference from corundum is ordering: Fe²⁺ and Ti⁴⁺ occupy alternate layers of octahedral sites in an ordered fashion. It can be viewed as an ordered derivative of the corundum structure.
Applications
⚡ Ferroelectrics
BaTiO₃ (barium titanate) is a perovskite used in capacitors, transducers and memory devices because of its ferroelectricity.
☀️ Solar cells
Halide perovskites like CH₃NH₃PbI₃ are the active layer in low-cost, high-efficiency perovskite solar cells.
🧲 Multiferroics & catalysts
Perovskites such as LaMnO₃ are used in solid-oxide fuel-cell electrodes and oxidation catalysts.
⛏️ Ilmenite ore
FeTiO₃ is the main ore of titanium metal and TiO₂ pigment.
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Spinel Structure (AB₂O₄)
The mineral spinel is MgAl₂O₄. General formula AB₂O₄: O²⁻ ions form a ccp lattice; the A²⁺ and B³⁺ cations distribute themselves between the tetrahedral and octahedral voids. How they distribute gives two types:
Point
Normal Spinel
Inverse Spinel
General formula
A²⁺[B³⁺₂]O₄
B³⁺[A²⁺B³⁺]O₄
Tetrahedral sites (1/8 filled)
A²⁺ ions
Half of the B³⁺ ions
Octahedral sites (1/2 filled)
B³⁺ ions
A²⁺ ions + remaining B³⁺ ions
Examples
MgAl₂O₄, ZnFe₂O₄, MnAl₂O₄
Fe₃O₄ (magnetite), NiFe₂O₄, CoFe₂O₄
Spinel Structure (AB₂O₄)
Oxide ions are cubic close packed. In a normal spinel (MgAl₂O₄) the A cation takes 1/8 of tetrahedral holes and B takes 1/2 of octahedral holes; inverse spinels (Fe₃O₄) swap half the B ions into tetrahedral holes.
Degree of inversion: Real spinels often lie between the two extremes. The fraction of A²⁺ ions present in octahedral sites is called the inversion parameter — 0 for a perfect normal spinel and 1 for a perfect inverse spinel. Crystal field stabilisation energy (CFSE) decides the preference: ions with high octahedral CFSE (like Ni²⁺, Cr³⁺) prefer octahedral sites.
Cation distribution and magnetic implications
In magnetite, Fe₃O₄ (inverse spinel, Fe³⁺[Fe²⁺Fe³⁺]O₄), the magnetic moments of Fe³⁺ ions in tetrahedral sites align antiparallel to those in octahedral sites, so they cancel each other.
The net magnetic moment comes only from the Fe²⁺ ions in octahedral sites (4 unpaired electrons → 4 Bohr magnetons per formula unit).
This antiparallel-but-unequal arrangement is called ferrimagnetism — the reason magnetite is a natural magnet (lodestone).
Exam tip: For "explain the magnetism of Fe₃O₄", write three lines: (1) inverse spinel — Fe³⁺ in tetrahedral, Fe²⁺ + Fe³⁺ in octahedral; (2) tetrahedral and octahedral Fe³⁺ moments are antiparallel and cancel; (3) net moment = 4 BM from Fe²⁺ → ferrimagnetism. Full marks.
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Diamond Cubic Structure
Arrangement: Carbon atoms form a ccp lattice, and additional carbon atoms occupy half of the tetrahedral voids.
Coordination number: 4 — every carbon is tetrahedrally bonded to 4 others by strong covalent bonds.
Atoms per unit cell: 8 (4 from the ccp lattice + 4 from the filled tetrahedral voids).
Examples: Diamond (C), silicon (Si), germanium (Ge) — the basis of the semiconductor industry.
The strong directional covalent bonding in 3D gives diamond its extreme hardness and high melting point.
Diamond Cubic Structure
Carbon atoms sit on a ccp lattice with half the tetrahedral voids also filled by carbon — every carbon is tetrahedrally bonded to 4 neighbours.
Diamond vs Zinc Blende vs Wurtzite — quick comparison
Point
Diamond
Zinc Blende
Wurtzite
Packing of main atoms
ccp of C
ccp of S²⁻
hcp of S²⁻
Atoms in tetrahedral voids
C (half of voids)
Zn²⁺ (half of voids)
Zn²⁺ (half of voids)
Stacking
ABCABC…
ABCABC…
ABAB…
Coordination
4 (all C)
4 : 4
4 : 4
Atoms per unit cell
8
4 ZnS units
2 ZnS units
Bonding character
Pure covalent
Covalent + partial ionic
Covalent + partial ionic
Memory trick: Diamond is just "zinc blende with both atoms the same" — ccp lattice + half tetrahedral voids filled, CN 4. If you know zinc blende, you know diamond; only the stacking (ABC vs AB) separates zinc blende from wurtzite.
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Silicates — Structures Built from SiO₄ Tetrahedra
The basic building block of every silicate is the SiO₄ tetrahedron — one silicon atom at the centre, tetrahedrally bonded to four oxygen atoms. Silicates are classified by how many oxygens each tetrahedron shares with its neighbours. More sharing = more polymerised = higher Si : O ratio.
SiO₄ Tetrahedron — Basic Unit of Silicates
Silicon sits at the centre of a tetrahedron of four oxygens. Tetrahedra link by sharing corner oxygens (Si–O–Si) to build every silicate structure.
Type
Sharing
Basic unit / formula
Examples
Ortho / Neso (isolated)
No sharing
SiO₄⁴⁻
Olivine (Mg₂SiO₄), garnet, willemite (Zn₂SiO₄)
Pyro / Soro (paired)
1 oxygen shared
Si₂O₇⁶⁻
Thortveitite (Sc₂Si₂O₇)
Cyclo (rings)
2 oxygens, closed ring
(SiO₃)₃⁶⁻, (Si₆O₁₈)¹²⁻
Beryl (Be₃Al₂Si₆O₁₈), tourmaline
Single chain — pyroxenes
2 oxygens shared
(SiO₃)ₙ²ⁿ⁻
Diopside CaMg(SiO₃)₂, spodumene
Double chain — amphiboles
2–3 oxygens shared
(Si₄O₁₁)ₙ⁶ⁿ⁻
Tremolite, asbestos minerals, hornblende
Sheet — phyllosilicates
3 oxygens shared
(Si₂O₅)ₙ²ⁿ⁻
Talc, muscovite mica, clay minerals (kaolinite)
Framework — tectosilicates
All 4 oxygens shared
SiO₂
Quartz, feldspars, zeolites
Sheet silicates in daily life
🪶 Talc
Mg₃(Si₄O₁₀)(OH)₂ — softest mineral (hardness 1); sheets slide easily, used in talcum powder and lubricants.
✨ Mica (muscovite)
KAl₂(AlSi₃O₁₀)(OH)₂ — perfect basal cleavage into thin transparent sheets; electrical insulator used in electronics.
🏺 Clay minerals
Kaolinite Al₂Si₂O₅(OH)₄ — fine sheets that absorb water; basis of pottery, ceramics and paper coating.
🪟 Zeolites (framework)
Open 3D framework with cages and channels; used as molecular sieves, catalysts and water softeners (see below).
Isomorphous substitution and ion exchange
Isomorphous substitution means one ion replaces another of similar size in the crystal without changing the structure — e.g. Al³⁺ replaces Si⁴⁺ in the SiO₄ tetrahedra of sheet and framework silicates.
Since Al³⁺ has one less positive charge than Si⁴⁺, the framework gains a net negative charge.
This charge is balanced by loosely held cations (Na⁺, K⁺, Ca²⁺) sitting in the interlayer spaces or cavities.
These cations are not fixed — they can be exchanged for other cations from solution. This is the ion-exchange property of clays and zeolites.
Zeolites — industrial applications
Water softening (permutit process): sodium zeolite exchanges its Na⁺ for Ca²⁺ and Mg²⁺ in hard water: Na₂-zeolite + Ca²⁺ → Ca-zeolite + 2Na⁺.
Molecular sieves: uniform cage/channel sizes trap only molecules small enough to enter — used for drying gases and separating mixtures.
Catalysis: zeolites like ZSM-5 are solid-acid catalysts in petroleum cracking and petrochemical manufacture.
Detergents: zeolite A replaces phosphates as a builder, softening wash water.
Exam tip: The classic 5-mark question is "Classify silicates based on SiO₄ linkage with one example each." Draw the table above, add the Si : O ratio logic (isolated SiO₄ → SiO₂ framework), and finish with isomorphous substitution → ion exchange → zeolite uses. That single answer covers three syllabus points at once.
✎ PYQ Zone — Chapter 4
Every previous-year question from this chapter's topics, with year, paper, marks and a full exam-ready answer. Tap a question to open its detailed solution.
2020B.Sc. CC-115 marks🔁 also 2024
Q5 — “What are spinels? Using crystal field model, explain why Fe₃O₄ has an inverse spinel structure while Mn₃O₄ has a normal spinel structure. A complex of a transition metal ion with d⁶ electronic configuration is diamagnetic; is it an octahedral or a tetrahedral one?” ⭐⭐⭐⭐
Repeated: 2024 · B.Sc. CC-11 · Q2(a)(i) (“Using CFSE indicate spinels to be normal or inverse: Mn₃O₄, Fe₃O₄”, 2+2 marks)
📖 Detailed answer ▼
Spinels are oxides of formula AB₂O₄ built on a cubic close-packed array of O²⁻ ions. Per unit cell, 8 tetrahedral (A) holes and 16 octahedral (B) holes are filled by cations.
Normal spinel: A²⁺ in tetrahedral + 2B³⁺ in octahedral → AII[B₂III]O₄. Example: MgAl₂O₄, Mn₃O₄.
Inverse spinel: B³⁺ in tetrahedral + (A²⁺ + B³⁺) in octahedral → BIII[AIIBIII]O₄. Example: Fe₃O₄ (magnetite).
CFSE decides the sites (octahedral, high-spin values):
Ion
Configuration
CFSE (Oh)
Mn²⁺ / Fe³⁺
d⁵ high-spin
0
Fe²⁺
d⁶ high-spin
−0.4Δ₀
Mn³⁺
d⁴ high-spin
−0.6Δ₀
Fe₃O₄ = inverse spinel. The only ion with an octahedral preference is Fe²⁺ (−0.4Δ₀); Fe³⁺ (d⁵) has none. Fe²⁺ claims an octahedral site, pushing one Fe³⁺ into the tetrahedral site: FeIII[FeIIFeIII]O₄.
Mn₃O₄ = normal spinel.Mn³⁺ (d⁴, −0.6Δ₀, also Jahn–Teller stabilised in octahedral geometry) outranks Mn²⁺ (d⁵, zero preference). Both Mn³⁺ ions take octahedral sites and Mn²⁺ takes the tetrahedral site: MnII[Mn₂III]O₄.
The d⁶ half: a diamagnetic d⁶ ion has all six electrons paired → t2g⁶, which is possible only in a low-spin octahedral complex (strong field). Tetrahedral splitting Δt is always small (≈ 4/9 Δ₀), so tetrahedral complexes are always high-spin — d⁶ tetrahedral is e³t₂³ with 4 unpaired electrons, hence paramagnetic. Answer: it must be an octahedral complex.
2021B.Sc. CC-115 marks
Q3(a) — “What type of spinel structure do you expect for Co₃O₄ and NiCr₂O₄? Explain on the basis of CFT.” ⭐⭐⭐
📖 Detailed answer ▼
Rule: the ion with the larger octahedral-site preference energy claims the 16 octahedral B-sites; the other ion takes the 8 tetrahedral A-sites.
Co₃O₄ = NORMAL spinel: CoII[Co₂III]O₄. The deciding ion is Co³⁺: even in the weak oxide field it is low-spin d⁶ (t2g⁶) with an enormous octahedral CFSE of −2.4Δ₀ (plus pairing energy 2P) — far larger than the octahedral preference of Co²⁺ (high-spin d⁷, −0.8Δ₀). Both Co³⁺ ions therefore occupy octahedral sites and Co²⁺ goes tetrahedral. (Confirmed experimentally: Co₃O₄ contains diamagnetic low-spin Co³⁺ in octahedral holes; its magnetism comes from tetrahedral Co²⁺.)
NiCr₂O₄ = NORMAL spinel: NiII[Cr₂III]O₄.Cr³⁺ (d³) has the largest octahedral-site preference of the common 3d ions (CFSE −1.2Δ₀ — bigger than the site preference of Ni²⁺, d⁸), so both Cr³⁺ ions firmly take the octahedral sites and Ni²⁺ sits in the tetrahedral site.
Exam trap: both are normal — students often guess “inverse” for the chromite because Ni²⁺ also likes octahedral sites, but Cr³⁺’s octahedral preference is larger, so Cr³⁺ wins the octahedral holes.
2024B.Sc. CC-112+2 marks🔁 also 2020
Q2(a)(i) — “Using crystal field stabilization energy (CFSE) indicate spinels to be normal or inverse: Mn₃O₄, Fe₃O₄” ⭐⭐⭐⭐
CFSE in octahedral field (high-spin): d⁵ (Mn²⁺, Fe³⁺) = 0; d⁶ (Fe²⁺) = −0.4Δ₀; d⁴ (Mn³⁺) = −0.6Δ₀. The ion with the bigger octahedral CFSE takes the octahedral B-sites.
Mn₃O₄ = NORMAL: MnII[Mn₂III]O₄. Mn³⁺ (d⁴, −0.6Δ₀, Jahn–Teller active) strongly prefers octahedral; Mn²⁺ (d⁵, CFSE = 0) has no preference and goes tetrahedral.
Fe₃O₄ = INVERSE: FeIII[FeIIFeIII]O₄. Fe²⁺ (d⁶, −0.4Δ₀) is the only ion with an octahedral preference, so it claims an octahedral site and displaces one Fe³⁺ (d⁵, no preference) into the tetrahedral site.
One line: the ion with non-zero octahedral CFSE wins the octahedral holes — Mn³⁺ in Mn₃O₄ (normal), Fe²⁺ in Fe₃O₄ (inverse).
2019B.Sc. CC-92 marks
Q3(c)(iii) — “What are pyroxene and amphibole? Illustrate structurally.” ⭐⭐⭐
📖 Detailed answer ▼
Both are chain silicates — families of silicate minerals distinguished by how SiO₄ tetrahedra share corner oxygens.
Pyroxene — single chain. Each SiO₄ tetrahedron shares 2 of its 4 oxygens (2 bridging + 2 terminal), giving the repeating unit (SiO₃)ₙ²ⁿ⁻ (O:Si = 3:1). Examples: diopside CaMg(SiO₃)₂, jadeite NaAl(SiO₃)₂.
Amphibole — double chain. Two single chains cross-link: alternate tetrahedra share an extra oxygen, so each SiO₄ shares 2 or 3 oxygens, giving (Si₄O₁₁)ₙ⁶ⁿ⁻ (O:Si = 2.75:1). The cavity in the double chain holds OH⁻ groups. Examples: tremolite Ca₂Mg₅(Si₄O₁₁)₂(OH)₂, asbestos minerals.
Structural sketch: draw each SiO₄ as a triangle; join triangles corner-to-corner in a single row for pyroxene. For amphibole, draw two such rows side by side and link them through shared corners — the result is a ladder-like double chain. Cations (Ca²⁺, Mg²⁺) sit between the chains balancing the charge.